The truth table for the circuit given in the fig. is:

$\displaystyle \left|\begin{array}{ccc} \mathrm{A} & \mathrm{~B} & \mathrm{Y} \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 0 \\ 1 & 1 & 0 \end{array}\right|$

$\displaystyle \left|\begin{array}{ccc} \mathrm{A} & \mathrm{~B} & \mathrm{Y} \\ 0 & 0 & 0 \\ 0 & 1 & 0 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \end{array}\right|$

$\displaystyle \left|\begin{array}{ccc} \mathrm{A} & \mathrm{~B} & \mathrm{Y} \\ 0 & 0 & 1 \\ 0 & 1 & 0 \\ 1 & 0 & 0 \\ 1 & 1 & 0 \end{array}\right|$

$\displaystyle \left|\begin{array}{ccc} \mathrm{A} & \mathrm{~B} & \mathrm{Y} \\ 0 & 0 & 1 \\ 0 & 1 & 1 \\ 1 & 0 & 1 \\ 1 & 1 & 1 \end{array}\right|$