Physics · 2023
JEE Main · 8 April 2023, Shift 2 · Q39
The trajectory of projectile, projected from the ground is given by y=x-x^2/20. Where x and y are measured in meter. The maximum height attained by…
The trajectory of projectile, projected from the ground is given by $\displaystyle y=x-\frac{x^2}{20}$. Where $\displaystyle x$ and $\displaystyle y$ are measured in meter. The maximum height attained by the projectile will be.
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 5$ m
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.