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Physics · 2026

JEE Main · 28 January 2026, Shift 2 · Q27

The time period of a simple harmonic oscillator is T=2 π √(k/m). Measured value of mass (m) of the object is 10 g with an accuracy of 10 mg and time…

The time period of a simple harmonic oscillator is $\displaystyle T=2 \pi \sqrt{\frac{k}{m}}$. Measured value of mass $\displaystyle (m)$ of the object is $\displaystyle 10$ g with an accuracy of $\displaystyle 10$ mg and time for $\displaystyle 50$ oscillations of the spring is found to be $\displaystyle 60$ s using a watch of $\displaystyle 2$ s resolution. Percentage error in determination of spring constant $\displaystyle (k)$ is $\displaystyle \_\_\_\_$ %.
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.