Physics · 2023
JEE Main · 10 April 2023, Shift 2 · Q37
The time period of a satellite, revolving above earth's surface at a height equal to R will be (Given g =π^2 m / s^2, R = radius of earth)
The time period of a satellite, revolving above earth's surface at a height equal to R will be
(Given $\displaystyle \mathrm{g}=\pi^2 \mathrm{~m} / \mathrm{s}^2, \mathrm{R}=$ radius of earth)
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle \sqrt{32 \mathrm{R}}$
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.