Physics · 2023
JEE Main · 11 April 2023, Shift 2 · Q52
The surface tension of soap solution is 3.5 × 10^-2 Nm^-1. The amount of work done required to increase the radius of soap bubble from 10 cm to 20 cm…
The surface tension of soap solution is $\displaystyle 3.5 \times 10^{-2} \mathrm{Nm}^{-1}$. The amount of work done required to increase the radius of soap bubble from $\displaystyle 10$ cm to $\displaystyle 20$ cm is
$\displaystyle \_\_\_\_$ $\displaystyle \times 10^{-4} \mathrm{~J}$.
(take $\displaystyle \pi=22 / 7$ )
Official answer
From NTA’s final answer key for this paper.
264
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.