Physics · 2016
JEE Main · 10 April 2016, Shift 1 · Q14
The resistance of an electrical toaster has a temperature dependence given by R(T)=R_0[1+α(T-T_0)] in its range of operation. At T_0=300 K, R=100 Ω…
The resistance of an electrical toaster has a temperature dependence given by $\displaystyle R(T)=R_0\left[1+\alpha\left(T-T_0\right)\right]$ in its range of operation. At $\displaystyle T_0=300 \mathrm{~K}, R=100 \Omega$ and at $\displaystyle T=500 \mathrm{~K}, R=120 \Omega$. The toaster is connected to a voltage source at $\displaystyle 200$ V and its temperature is raised at a constant rate from $\displaystyle 300$ to $\displaystyle 500$ K in $\displaystyle 30$ s. The total work done in raising the temperature is :
Official answer
(1)
$\displaystyle 400 \ln \frac{1.5}{1.3} \mathrm{~J}$
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JEE Main 2016 Physics question, with the answer from NTA’s final answer key. Where our answers come from.