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Physics · 2021

JEE Main · 18 March 2021, Shift 2 · Q30

The radius of a sphere is measured to be (7.50 ± 0.85) cm. Suppose the percentage error in its volume is x. The value of x, to the nearest x, is \ \…

The radius of a sphere is measured to be $\displaystyle (7.50 \pm 0.85) \mathrm{cm}$. Suppose the percentage error in its volume is $\displaystyle x$.The value of $\displaystyle x$, to the nearest $\displaystyle x$, is \_\_\_\_.
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.