Physics · 2024
JEE Main · 29 January 2024, Shift 1 · Q35
The potential energy function (in J ) of a particle in a region of space is given as U=(2 x^2+3 y^3+2 z). Here x, y and z are in meter. The magnitude…
The potential energy function (in $\displaystyle J$ ) of a particle in a region of space is given as $\displaystyle U=\left(2 x^2+3 y^3+2 z\right)$. Here $\displaystyle x, y$ and $\displaystyle z$ are in meter. The magnitude of $\displaystyle x$ - component of force (in $\displaystyle N$ ) acting on the particle at point $\displaystyle P(1,2,3) \mathrm{m}$ is :
Official answer
From NTA’s final answer key for this paper.
(2)
$\displaystyle 4$
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.