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Physics · 2014

JEE Main · 9 April 2014, Shift 1 · Q2

The position of a projectile launched from the origin at t =0 is given by r =(40 i +50 j ) m at t =2 s. If the projectile was launched at an angle θ…

The position of a projectile launched from the origin at $\displaystyle \mathrm{t}=0$ is given by $\displaystyle \overrightarrow{\mathrm{r}}=(40 \hat{i}+50 \hat{j}) \mathrm{m}$ at $\displaystyle \mathrm{t}=2 \mathrm{~s}$. If the projectile was launched at an angle $\displaystyle \theta$ from the horizontal, then $\displaystyle \theta$ is (take $\displaystyle \mathrm{g}=10 \mathrm{~ms}^{-2}$ ).
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JEE Main 2014 Physics question, with the answer from NTA’s final answer key. Where our answers come from.