Physics · 2021
JEE Main · 25 February 2021, Shift 1 · Q11
The pitch of the screw gauge is 1 mm and there are 100 divisions on the circular scale. When nothing is put in between the jaws, the zero of the…
The pitch of the screw gauge is $\displaystyle 1$ mm and there are $\displaystyle 100$ divisions on the circular scale. When nothing is put in between the jaws, the zero of the circular scale lies $\displaystyle 8$ divisions below the reference line. When a wire is placed between the jaws, the first linear scale division is clearly visible while $\displaystyle 72^{\text {nd }}$ division on circular scale coincides with the reference line. The radius of the wire is :
Official answer
(3)
0.$\displaystyle 82$ mm
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.