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Physics · 2015
JEE Main 2015 · 2015-04-04 Offline · Q2
The period of oscillation of a simple pendulum is T =2 π √(L/g). Measured value of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillations…
The period of oscillation of a simple pendulum is $\displaystyle \mathrm{T}=2 \pi \sqrt{\frac{\mathrm{~L}}{\mathrm{~g}}}$. Measured value of L is $\displaystyle 20.0$ cm known to $\displaystyle 1$ mm accuracy and time for $\displaystyle 100$ oscillations of the pendulum is found to be $\displaystyle 90$ s using a wrist watch of 1s resolution. The accuracy in the determination of g is :
Official answer
(2)
$\displaystyle 3$ %
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JEE Main 2015 Physics question, with the answer from NTA’s final answer key. Where our answers come from.