The peak electric field produced by the radiation coming from the 8 W bulb at a distance of 10 m is x/10 √((μ_0 c)/(π)) V/m. The efficiency of the…

The peak electric field produced by the radiation coming from the $\displaystyle 8$ W bulb at a distance of $\displaystyle 10$ m is $\displaystyle \frac{x}{10} \sqrt{\frac{\mu_0 \mathrm{c}}{\pi}} \frac{\mathrm{V}}{\mathrm{m}}$. The efficiency of the bulb is $\displaystyle 10 \%$ and it is a point source. The value of $\displaystyle x$ is \_\_\_\_.