SolveIt is under development
SolveItJEE Main
Physics · 2019

JEE Main · 8 April 2019, Shift 2 · Q22

The magnetic field of an electromagnetic wave is given by: B =1.6 × 10^-6 cos (2 × 10^7 z +6 × 10^15 t )(2 i + j ) Wb/(m^2) The associated electric…

The magnetic field of an electromagnetic wave is given by : $$\overrightarrow{\mathrm{B}}=1.6 \times 10^{-6} \cos \left(2 \times 10^7 \mathrm{z}+6 \times 10^{15} \mathrm{t}\right)(2 \hat{i}+\hat{j}) \frac{\mathrm{Wb}}{\mathrm{~m}^2} $$ The associated electric field will be :
ShareWhatsAppTelegram

More from Electromagnetic Waves

JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.