Physics · 2025
JEE Main · 28 January 2025, Shift 2 · Q40
The magnetic field of an E.M. wave is given by B =((√ 3)/2 i +1/2 j ) 30 sin [ω( t -z/c)] (S.I. Units). The corresponding electric field in S.I.…
The magnetic field of an E.M. wave is given by $\displaystyle \overrightarrow{\mathrm{B}}=\left(\frac{\sqrt{3}}{2} \hat{i}+\frac{1}{2} \hat{j}\right) 30 \sin \left[\omega\left(\mathrm{t}-\frac{z}{\mathrm{c}}\right)\right]$ (S.I. Units). The corresponding electric field in S.I. units is :
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \overrightarrow{\mathrm{E}}=\left(\frac{1}{2} \hat{i}-\frac{\sqrt{3}}{2} \hat{j}\right) 30 \mathrm{c} \sin \left[\omega\left(\mathrm{t}-\frac{z}{\mathrm{c}}\right)\right]$
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JEE Main 2025 Physics question, with the answer from NTA’s final answer key. Where our answers come from.