Physics · 2020
JEE Main · 3 September 2020, Shift 1 · Q16
The magnetic field of a plane electromagnetic wave is B =3 × 10^-8 sin [200 π(y+ ct )] i T where c =3 × 10^8 ms^-1 is the speed of light. The…
The magnetic field of a plane electromagnetic wave is
$$\overrightarrow{\mathrm{B}}=3 \times 10^{-8} \sin [200 \pi(y+\mathrm{ct})] \hat{i} \mathrm{~T}
$$
where $\displaystyle \mathrm{c}=3 \times 10^8 \mathrm{~ms}^{-1}$ is the speed of light.
The corresponding electric field is :
Official answer
(2)
$\displaystyle \overrightarrow{\mathrm{E}}=-9 \sin [200 \pi(y+\mathrm{ct})] \hat{\mathrm{k}} \mathrm{~V} / \mathrm{m}$
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.