Physics · 2021
JEE Main · 4 August 2021, Shift 1 · Q14
The magnetic field in any region is given by B = B_0(2+x/a) k. A square loop of edge length ' l ' is placed with its edge along x and y axis. The…
The magnetic field in any region is given by $\displaystyle \overrightarrow{\mathrm{B}}=\mathrm{B}_0\left(2+\frac{\mathrm{x}}{\mathrm{a}}\right) \hat{\mathrm{k}}$. A square loop of edge length ' $\displaystyle l$ ' is placed with its edge along x and y axis. The loop is moved with
a constant velocity $\displaystyle \overline{\mathrm{v}}=\mathrm{v}_0 \hat{\mathrm{i}}$.
The emf induced in the loop will be -
Official answer
(3)
$\displaystyle \mathrm{v}_0 \mathrm{~B}_0 \frac{\ell^2}{\mathrm{a}}$
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.