Physics · 2022
JEE Main · 25 July 2022, Shift 2 · Q43
The length of a seconds pendulum at a height h =2 R from earth surface will be: (Given R = Radius of earth and acceleration due to gravity at the…
The length of a seconds pendulum at a height $\displaystyle \mathrm{h}=2 \mathrm{R}$ from earth surface will be :
(Given $\displaystyle \mathrm{R}=$ Radius of earth and acceleration due to gravity at the surface of earth,
$$\left.\mathrm{g}=\pi^2 \mathrm{~ms}^{-2}\right)
$$
Official answer
(4)
$\displaystyle \frac{1}{9} \mathrm{~m}$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.