Physics · 2019
JEE Main · 12 January 2019, Shift 1 · Q29
The galvanometer deflection, when key K_1 is closed but K_2 is open, equals θ_0 (see figure). On closing K_2 also and adjusting R_2 to 5 Ω, the…
The galvanometer deflection, when key $\displaystyle \mathrm{K}_1$ is closed but $\displaystyle \mathrm{K}_2$ is open, equals $\displaystyle \theta_0$ (see figure). On closing $\displaystyle \mathrm{K}_2$ also and adjusting $\displaystyle \mathrm{R}_2$ to $\displaystyle 5 \Omega$, the deflection in galvanometer becomes $\displaystyle \frac{\theta_0}{5}$. The resistance of the galvanometer is, then, given by [Neglect the internal resistance of battery] :

Official answer
(1)
$\displaystyle 22 \Omega$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.