Physics · 2022
JEE Main · 28 July 2022, Shift 1 · Q36
The force required to stretch a wire of cross-section 1 cm^2 to double its length will be: (Given Yong's modulus of the wire =2 × 10^11 N / m^2 )
The force required to stretch a wire of cross-section $\displaystyle 1 \mathrm{~cm}^2$ to double its length will be : (Given Yong's modulus of the wire $\displaystyle =2 \times 10^{11} \mathrm{~N} / \mathrm{m}^2$ )
Official answer
(3)
$\displaystyle 2 \times 10^7 \mathrm{~N}$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.