Physics · 2019
JEE Main · 11 January 2019, Shift 1 · Q1
The force of interaction between two atoms is given by F =α β exp (-x^2/(α kt)); where x is the distance, k is the Boltzmann constant and T is…
The force of interaction between two atoms is given by $\displaystyle \mathrm{F}=\alpha \beta \exp \left(-\frac{x^2}{\alpha \mathrm{kt}}\right)$; where $\displaystyle x$ is the distance, k is the Boltzmann constant and T is temperature and $\displaystyle \alpha$ and $\displaystyle \beta$ are two constants. The dimension of $\displaystyle \beta$ is :
Official answer
(4)
$\displaystyle \mathrm{M}^2 \mathrm{LT}^{-4}$
More from Units and Dimensions
- The de-Broglie wavelength associated with a particle of mass m and energy E is h / √(2 m E). The dimensional formula for Planck's constant is:2024
- If E and H represents the intensity of electric field and magnetising field respectively, then the unit of E/H will be:2021
- If B is magnetic field and μ_0 is permeability of free space, then the dimensions of (B / μ_0) is2025
- L, C and R represents physical quantities inductance, capacitance and resistance respectively. The dimensional formula M L^2 T^-4 A^-2 corresponds to…2026
- If current ( I ), kinetic energy ( K ) and charge ( Q ) are taken as the fundamental quantities, The dimensional representation of power will be:2022
- If the velocity of light c, universal gravitational constant G and Planck's constant h are chosen as fundamental quantities. The dimensions of mass…2023
- A quantity f is given by f=√((hc^5)/G) where c is speed of light, G universal gravitational constant and h is the Planck's constant. Dimension of f…2020
- A quantity x is given by ( IF v^2 / WL^4 )in terms of moment of inertia I, force F, velocity v, work W and Length L. The dimensional formula for x is…2020
JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.