Physics · 2014
JEE Main · 9 April 2014, Shift 1 · Q12
The equation of state for a gas is given by PV = nRT +α V, where n is the number of moles and α is a positive constant. The initial temperature and…
The equation of state for a gas is given by $\displaystyle \mathrm{PV}=\mathrm{nRT}+\alpha \mathrm{V}$, where n is the number of moles and $\displaystyle \alpha$ is a positive constant. The initial temperature and pressure of one mole of the gas contained in a cylinder are $\displaystyle \mathrm{T}_{\mathrm{o}}$ and $\displaystyle \mathrm{P}_{\mathrm{o}}$ respectively. The work done by the gas when its temperature doubles isobarically will be :
Official answer
(1)
$\displaystyle \frac{P_o T_o R}{P_o-\alpha}$
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JEE Main 2014 Physics question, with the answer from NTA’s final answer key. Where our answers come from.