Physics · 2019
JEE Main · 9 January 2019, Shift 2 · Q8
The energy required to take a satellite to a height 'h' above Earth surface (radius of Earth =6.4 × 10^3 km ) is E_1 and kinetic energy required for…
The energy required to take a satellite to a height 'h' above Earth surface (radius of Earth $\displaystyle =6.4 \times 10^3 \mathrm{~km}$ ) is $\displaystyle \mathrm{E}_1$ and kinetic energy required for the satellite to be in a circular orbit at this height is $\displaystyle \mathrm{E}_2$. The value of h for which $\displaystyle \mathrm{E}_1$ and $\displaystyle \mathrm{E}_2$ are equal, is :
Official answer
(4)
$\displaystyle 3.2 \times 10^3 \mathrm{~km}$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.