Physics · 2020
JEE Main · 9 January 2020, Shift 1 · Q14
The electric fields of two plane electromagnetic plane waves in vacuum are given by E_1= E_0 j cos (ω t - k x) and E_2= E_0 k cos (ω t - k y) At t…
The electric fields of two plane electromagnetic plane waves in vacuum are given by
$$\begin{aligned}
& \overrightarrow{\mathrm{E}}_1=\mathrm{E}_0 \hat{j} \cos (\omega \mathrm{t}-\mathrm{k} x) \text { and } \\
& \overrightarrow{\mathrm{E}}_2=\mathrm{E}_0 \hat{k} \cos (\omega \mathrm{t}-\mathrm{k} y)
\end{aligned}
$$
At $\displaystyle \mathrm{t}=0$, a particle of charge q is at origin with a velocity $\displaystyle \overrightarrow{\mathrm{v}}=0.8 \mathrm{c} \hat{j}$ (c is the speed of light in vaccum). The instantaneous force experienced by the particle is :
Official answer
(2)
$\displaystyle \mathrm{E}_0 \mathrm{q}(0.8 \hat{i}+\hat{j}+0.2 \hat{k})$
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.