The electric field of a plane electromagnetic wave is given by E = E_0 (i + j)/(√ 2) cos ( k z+ω t ) At t =0, a positively charged particle is at the…

The electric field of a plane electromagnetic wave is given by $$\overrightarrow{\mathrm{E}}=\mathrm{E}_0 \frac{\hat{i}+\hat{j}}{\sqrt{2}} \cos (\mathrm{k} z+\omega \mathrm{t}) $$ At $\displaystyle \mathrm{t}=0$, a positively charged particle is at the point $\displaystyle (x, y, z)=\left(0,0, \frac{\pi}{k}\right)$. If its instantaneous velocity at $\displaystyle (\mathrm{t}=0)$ is $\displaystyle v_0 \hat{k}$, the force acting on it due to the wave is :