Physics · 2014
JEE Main · 19 April 2014, Shift 1 · Q16
The electric field in a region of space is given by, E = E_o i +2 E_o j where E_0=100 N / C. The flux of this field through a circular surface of…
The electric field in a region of space is given by, $\displaystyle \overrightarrow{\mathrm{E}}=\mathrm{E}_{\mathrm{o}} \hat{i}+2 \mathrm{E}_{\mathrm{o}} \hat{j}$ where $\displaystyle \mathrm{E}_0=100 \mathrm{~N} / \mathrm{C}$. The flux of this field through a circular surface of radius $\displaystyle 0.02$ m parallel to the Y-Z plane is nearly :
Official answer
(1)
$\displaystyle 0.125 \mathrm{Nm}^2 / \mathrm{C}$
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JEE Main 2014 Physics question, with the answer from NTA’s final answer key. Where our answers come from.