The electric field in a region is given by E =2/5 E_0 i +3/5 E_0 j with E_0=4.0 × 10^3 N/C. The flux of this field through a rectangular surface area…

The electric field in a region is given by $\displaystyle \overrightarrow{\mathrm{E}}=\frac{2}{5} \mathrm{E}_0 \hat{i}+\frac{3}{5} \mathrm{E}_0 \hat{j}$ with $\displaystyle \mathrm{E}_0=4.0 \times 10^3 \frac{\mathrm{~N}}{\mathrm{C}}$. The flux of this field through a rectangular surface area $\displaystyle 0.4 \mathrm{~m}^2$ parallel to the $\displaystyle \mathrm{Y}-\mathrm{Z}$ plane is \_\_\_\_ $\displaystyle \mathrm{Nm}^2 \mathrm{C}^{-1}$.