Physics · 2023
JEE Main · 24 January 2023, Shift 2 · Q15
The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by E_x= E_o sin ( kz -ω t ); B_y= B_o…
The electric field and magnetic field components of an electromagnetic wave going through vacuum is described by
$$\begin{aligned}
& \mathrm{E}_x=\mathrm{E}_{\mathrm{o}} \sin (\mathrm{kz}-\omega \mathrm{t}) \\
& \mathrm{B}_y=\mathrm{B}_{\mathrm{o}} \sin (\mathrm{kz}-\omega \mathrm{t})
\end{aligned}
$$
Then the correct relation between $\displaystyle \mathrm{E}_{\mathrm{o}}$ and $\displaystyle \mathrm{B}_{\mathrm{o}}$ is given by
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle \mathrm{kE}_{\mathrm{o}}=\omega \mathrm{B}_{\mathrm{o}}$
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.