Physics · 2019
JEE Main · 10 April 2019, Shift 1 · Q12
The displacement of a damped harmonic oscillator is given by x( t )= e^-0.1 t cos (10 π t +φ). Here t is in seconds. The time taken for its amplitude…
The displacement of a damped harmonic oscillator is given by $\displaystyle x(\mathrm{t})=\mathrm{e}^{-0.1 \mathrm{t}} \cos (10 \pi \mathrm{t}+\varphi)$. Here t is in seconds.The time taken for its amplitude of vibration to drop to half of its initial value is close to :
Official answer
(3)
$\displaystyle 7$ s
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.