Physics · 2022
JEE Main · 27 June 2022, Shift 2 · Q60
The cut-off voltage of the diodes (shown in figure) in forward bias is 0.6 V. The current through the resister of 40 Ω is \ \ \ \ mA.
The cut-off voltage of the diodes (shown in figure) in forward bias is $\displaystyle 0.6$ V . The current through the resister of $\displaystyle 40 \Omega$ is \_\_\_\_ mA.
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.