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Physics · 2014
JEE Main 2014 · 2014-04-06 Offline · Q1
The current voltage relation of diode is given by I =( e^1000 V / T -1) mA, where the applied voltage V is in volts and the temperature T is in…
The current voltage relation of diode is given by $\displaystyle \mathrm{I}=\left(\mathrm{e}^{1000 \mathrm{~V} / \mathrm{T}}-1\right) \mathrm{mA}$, where the applied voltage V is in volts and the temperature T is in degree Kelvin. If a student makes an error measuring $\displaystyle \pm 0.01 \mathrm{~V}$ while measuring the current of $\displaystyle 5$ mA at $\displaystyle 300$ K, what will be the error in the value of current in mA ?
Official answer
(1)
0.$\displaystyle 2$ mA
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JEE Main 2014 Physics question, with the answer from NTA’s final answer key. Where our answers come from.