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Physics · 2024

JEE Main · 5 April 2024, Shift 2 · Q59

The current in an inductor is given by I =(3 t +8) where t is in second. The magnitude of induced emf produced in the inductor is 12 mV. The…

The current in an inductor is given by $\displaystyle \mathrm{I}=(3 \mathrm{t}+8)$ where t is in second. The magnitude of induced emf produced in the inductor is $\displaystyle 12$ mV . The self-inductance of the inductor $\displaystyle \_\_\_\_$ mH.
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.