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Physics · 2019

JEE Main · 8 April 2019, Shift 1 · Q14

The bob of a simple pendulum has mass 2 g and a charge of 5.0 μ C. It is at rest in a uniform horizontal electric field of intensity 2000 V / m. At…

The bob of a simple pendulum has mass $\displaystyle 2$ g and a charge of $\displaystyle 5.0 \mu \mathrm{C}$. It is at rest in a uniform horizontal electric field of intensity $\displaystyle 2000 \mathrm{~V} / \mathrm{m}$. At equilibrium, the angle that the pendulum makes with the vertical is : $$\left(\text { take } \mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right) $$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.