Physics · 2020
JEE Main · 9 January 2020, Shift 1 · Q16
The aperture diameter of a telescope is 5 m. The separation between the moon and the earth is 4 × 10^5 km. With light of wavelength of 5500, the…
The aperture diameter of a telescope is $\displaystyle 5$ m . The separation between the moon and the earth is $\displaystyle 4 \times 10^5 \mathrm{~km}$. With light of wavelength of $\displaystyle 5500 \AA$, the minimum separation between objects on the surface of moon, so that they are just resolved, is close to :
Official answer
(2)
$\displaystyle 60$ m
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