Physics · 2024
JEE Main · 6 April 2024, Shift 2 · Q49
The acceptor level of a p-type semiconductor is 6 eV. The maximum wavelength of light which can create a hole would be: Given hc =1242 eV nm.
The acceptor level of a p-type semiconductor is $\displaystyle 6$ eV. The maximum wavelength of light which can create a hole would be : Given $\displaystyle \mathrm{hc}=1242 \mathrm{eV} \mathrm{nm}$.
Official answer
From NTA’s final answer key for this paper.
(1)
$\displaystyle 207$ nm
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.