Physics · 2021
JEE Main · 17 March 2021, Shift 2 · Q30
Suppose you have taken a dilute solution of oleic acid in such a way that its concentration becomes 0.01 cm^3 of oleic acid per cm^3 of the solution.…
Suppose you have taken a dilute solution of oleic acid in such a way that its concentration becomes $\displaystyle 0.01 \mathrm{~cm}^3$ of oleic acid per $\displaystyle \mathrm{cm}^3$ of the solution. Then you make a thin film of this solution (monomolecular thickness) of area $\displaystyle 4 \mathrm{~cm}^2$ by considering $\displaystyle 100$ spherical drops of radius $\displaystyle \left(\frac{3}{40 \pi}\right)^{\frac{1}{3}} \times 10^{-3} \mathrm{~cm}$. Then the thickness of oleic acid layer will be $\displaystyle x \times 10^{-14} \mathrm{~m}$. Where $\displaystyle x$ is \_\_\_\_.
Official answer
25
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.