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Physics · 2020

JEE Main · 6 September 2020, Shift 1 · Q25

Suppose that intensity of a laser is (315/(π)) W / m^2. The rms electric field, in units of V/m associated with this source is close to the nearest…

Suppose that intensity of a laser is $\displaystyle \left(\frac{315}{\pi}\right) \mathrm{W} / \mathrm{m}^2$. The rms electric field, in units of V/m associated with this source is close to the nearest integer is \_\_\_\_. $$\begin{aligned} & \left(\epsilon_0=8.86 \times 10^{-12} \mathrm{C}^2 \mathrm{Nm}^{-2} ; \mathrm{c}=3 \times 10^8\right. \\ & \left.\mathrm{ms}^{-1}\right) \end{aligned} $$
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.