Physics · 2020
JEE Main · 6 September 2020, Shift 1 · Q25
Suppose that intensity of a laser is (315/(π)) W / m^2. The rms electric field, in units of V/m associated with this source is close to the nearest…
Suppose that intensity of a laser is $\displaystyle \left(\frac{315}{\pi}\right) \mathrm{W} / \mathrm{m}^2$. The rms electric field, in units of V/m associated with this source is close to the nearest integer is
\_\_\_\_.
$$\begin{aligned}
& \left(\epsilon_0=8.86 \times 10^{-12} \mathrm{C}^2 \mathrm{Nm}^{-2} ; \mathrm{c}=3 \times 10^8\right. \\
& \left.\mathrm{ms}^{-1}\right)
\end{aligned}
$$
Official answer
275
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.