Physics · 2014
JEE Main · 12 April 2014, Shift 1 · Q8
Steel ruptures when a shear of 3.5 × 10^8 N m^-2 is applied. The force needed to punch a 1 cm diameter hole in a steel sheet 0.3 cm thick is nearly:
Steel ruptures when a shear of $\displaystyle 3.5 \times 10^8 \mathrm{~N} \mathrm{~m}^{-2}$ is applied. The force needed to punch a $\displaystyle 1$ cm diameter hole in a steel sheet $\displaystyle 0.3$ cm thick is nearly :
Official answer
(3)
$\displaystyle 3.3 \times 10^4 \mathrm{~N}$
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JEE Main 2014 Physics question, with the answer from NTA’s final answer key. Where our answers come from.