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Physics · 2020

JEE Main · 9 January 2020, Shift 2 · Q21

Starting at temperature 300 K, one mole of an ideal diatomic gas (γ=1.4) is first compressed adiabatically from volume V_1 to V_2=(V_1)/16. It is…

Starting at temperature $\displaystyle 300$ K , one mole of an ideal diatomic gas $\displaystyle (\gamma=1.4)$ is first compressed adiabatically from volume $\displaystyle \mathrm{V}_1$ to $\displaystyle \mathrm{V}_2=\frac{\mathrm{V}_1}{16}$. It is then allowed to expand isobarically to volume $\displaystyle 2 \mathrm{~V}_2$. If all the processes are the quasi-static then the final temperature of the gas (in $\displaystyle { }^{\circ} \mathrm{K}$ ) is (to the nearest integer) \_\_\_\_.
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