Physics · 2020
JEE Main · 8 January 2020, Shift 1 · Q12
Proton with kinetic energy of 1 MeV moves from south to north. It gets an acceleration of 10^12 m / s^2 by an applied magnetic field (west to east).…
Proton with kinetic energy of $\displaystyle 1$ MeV moves from south to north. It gets an acceleration of $\displaystyle 10^{12} \mathrm{~m} / \mathrm{s}^2$ by an applied magnetic field (west to east). The value of magnetic field : (Rest mass of proton is $\displaystyle 1.6 \times 10^{-27} \mathrm{~kg}$ )
Official answer
(3)
0.$\displaystyle 71$ mT
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.