Physics · 2019
JEE Main · 12 April 2019, Shift 2 · Q17
One kg of water, at 20^° C, is heated in an electric kettle whose heating element has a mean (temperature averaged) resistance of 20 Ω. The rms…
One kg of water, at $\displaystyle 20^{\circ} \mathrm{C}$, is heated in an electric kettle whose heating element has a mean (temperature averaged) resistance of $\displaystyle 20 \Omega$. The rms voltage in the mains is $\displaystyle 200$ V . Ignoring heat loss from the kettle, time taken for water to evaporate fully, is close to :
[Specific heat of water $\displaystyle =4200 \mathrm{~J} /\left(\mathrm{kg}{ }^{\circ} \mathrm{C}\right)$, Latent heat of water $\displaystyle =2260 \mathrm{~kJ} / \mathrm{kg}$ ]
Official answer
(3)
$\displaystyle 22$ minutes
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.