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Physics · 2020

JEE Main · 4 September 2020, Shift 1 · Q5

On the x -axis and at a distance x from the origin, the gravitational field due to a mass distribution is given by (A x)/((x^2+ a^2)^3 / 2) in the x…

On the $\displaystyle x$-axis and at a distance $\displaystyle x$ from the origin, the gravitational field due to a mass distribution is given by $\displaystyle \frac{\mathrm{A} x}{\left(x^2+\mathrm{a}^2\right)^{3 / 2}}$ in the $\displaystyle x$-direction. The magnitude of gravitational potential on the $\displaystyle x$-axis at a distance $\displaystyle x$, taking its value to be zero at infinity, is :
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JEE Main 2020 Physics question, with the answer from NTA’s final answer key. Where our answers come from.