Physics · 2022
JEE Main · 28 June 2022, Shift 1 · Q33
Motion of a particle in x-y plane is described by a set of following equations x=4 sin ((π)/2-ω t) m and y=4 sin (ω t) m. The path of the particle…
Motion of a particle in $\displaystyle x-y$ plane is described by a set of following equations $\displaystyle x=4 \sin \left(\frac{\pi}{2}-\omega t\right) \mathrm{m}$ and $\displaystyle y=4 \sin (\omega t) \mathrm{m}$. The path of the particle will be :
Official answer
(1)
circular
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.