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Physics · 2024

JEE Main · 6 April 2024, Shift 2 · Q35

Match List-I with List-II: List-I Y vs X List-II Shape of Graph (A) Y = magnetic susceptibility X = magnetising field (I) (B) Y = magnetic field…

Match List-I with List-II :
List-I
Y vs X
List-II
Shape of Graph
(A)
$\displaystyle \mathrm{Y}=$ magnetic susceptibility
X = magnetising field
(I)
Figure: JEE Main Physics 2024, Magnetic Field and Forces
(B)
$\displaystyle \mathrm{Y}=$ magnetic field
X=distance from centre of a current carrying wire for $\displaystyle x<\mathrm{a}$ (where $\displaystyle \mathrm{a}=$ radius of wire)
(II)
Figure: JEE Main Physics 2024, Magnetic Field and Forces
(C)
$\displaystyle Y=$ magnetic field
X=distance from centre of a current carrying wire for $\displaystyle x>\mathrm{a}$ (where $\displaystyle \mathrm{a}=$ radius of wire)
(III)
Figure: JEE Main Physics 2024, Magnetic Field and Forces
(D)
$\displaystyle \mathrm{Y}=$ magnetic field inside solenoid
X = distance from centre
(IV)
Figure: JEE Main Physics 2024, Magnetic Field and Forces
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JEE Main 2024 Physics question, with the answer from NTA’s final answer key. Where our answers come from.