Physics · 2023
JEE Main · 25 January 2023, Shift 1 · Q12
Match List I with List II & \\ A. & I. B_0=(μ_0 I)/(4 π r)[π+2] \\ B. & II. B_0=(μ_0)/4 I/r \\ C. & III. B_0=(μ_0 I)/(2 π r)[π-1] \\ D. & IV.…
Match List I with List II
Choose the correct answer from the options given below :
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| A. | I. $\displaystyle B_0=\frac{\mu_0 I}{4 \pi r}[\pi+2]$ | ||||
| B. | II. $\displaystyle B_0=\frac{\mu_0}{4} \frac{I}{r}$ | ||||
| C. | III. $\displaystyle B_0=\frac{\mu_0 I}{2 \pi r}[\pi-1]$ | ||||
| D. | IV. $\displaystyle B_0=\frac{\mu_0 I}{4 \pi r}[\pi+1]$ |
Official answer
From NTA’s final answer key for this paper.
(2)
A-III, B-I, C-IV, D-II
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JEE Main 2023 Physics question, with the answer from NTA’s final answer key. Where our answers come from.