Physics · 2022
JEE Main · 25 July 2022, Shift 2 · Q45
Let η_1 is the efficiency of an engine at T_1=447^° C and T_2=147^° C while η_2 is the efficiency at T_1=947^° C and T_2=47^° C The ratio (η_1)/(η_2)…
Let $\displaystyle \eta_1$ is the efficiency of an engine at $\displaystyle \mathrm{T}_1=447^{\circ} \mathrm{C}$ and $\displaystyle \mathrm{T}_2=147^{\circ} \mathrm{C}$ while $\displaystyle \eta_2$ is the efficiency at $\displaystyle \mathrm{T}_1=947^{\circ} \mathrm{C}$ and $\displaystyle \mathrm{T}_2=47^{\circ} \mathrm{C}$ The ratio $\displaystyle \frac{\eta_1}{\eta_2}$ will be :
Official answer
(2)
$\displaystyle 0.56$
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.