Physics · 2019
JEE Main · 12 April 2019, Shift 2 · Q15
Let a total charge 2 Q be distributed in a sphere of radius R, with the charge density given by ρ( r )= kr, where r is the distance from the centre.…
Let a total charge $\displaystyle 2$ Q be distributed in a sphere of radius R , with the charge density given by $\displaystyle \rho(\mathrm{r})=\mathrm{kr}$, where r is the distance from the centre. Two charges A and B, of -Q each, are placed on diametrically opposite points, at equal distance, a, from the centre. If A and B do not experience any force, then :
Official answer
(1)
$\displaystyle a=8^{-1 / 4} R$
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JEE Main 2019 Physics question, with the answer from NTA’s final answer key. Where our answers come from.