Physics · 2021
JEE Main · 25 February 2021, Shift 2 · Q8
Y = A sin (ω t +φ_0) is the time-displacement equation of a SHM. At t =0 the displacement of the particle is Y=A/2 and it is moving along negative x…
$\displaystyle \mathrm{Y}=\mathrm{A} \sin \left(\omega \mathrm{t}+\phi_0\right)$ is the time-displacement equation of a SHM. At $\displaystyle \mathrm{t}=0$ the displacement of the particle is $\displaystyle Y=\frac{A}{2}$ and it is moving along negative $\displaystyle x$-direction. Then the initial phase angle $\displaystyle \phi_0$ will be :
Official answer
(2)
$\displaystyle \frac{5 \pi}{6}$
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JEE Main 2021 Physics question, with the answer from NTA’s final answer key. Where our answers come from.