Physics · 2024
JEE Main · 5 April 2024, Shift 1 · Q58
In Young's double slit experiment, carried out with light of wavelength 5000, the distance between the slits is 0.3 mm and the screen is at 200 cm…
In Young's double slit experiment, carried out with light of wavelength $\displaystyle 5000 \AA$, the distance between the slits is $\displaystyle 0.3$ mm and the screen is at $\displaystyle 200$ cm from the slits. The central maximum is at $\displaystyle x=0 \mathrm{~cm}$. The value of $\displaystyle x$ for third maxima is $\displaystyle \_\_\_\_$ mm.
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From NTA’s final answer key for this paper.
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