Physics · 2022
JEE Main · 28 July 2022, Shift 1 · Q39
In the wave equation y=0.5 sin (2 π)/(λ)(400 t -x) m the velocity of the wave will be:
In the wave equation
$$y=0.5 \sin \frac{2 \pi}{\lambda}(400 \mathrm{t}-x) \mathrm{m}
$$
the velocity of the wave will be :
Official answer
(3)
$\displaystyle 400$ m/s
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JEE Main 2022 Physics question, with the answer from NTA’s final answer key. Where our answers come from.