Physics · 2026
JEE Main · 28 January 2026, Shift 1 · Q27
In the potentiometer, when the cell in the secondary circuit is shunted with 4 Ω resistance, the balance is obtained at the length 120 cm of wire.…
In the potentiometer, when the cell in the secondary circuit is shunted with $\displaystyle 4 \Omega$ resistance, the balance is obtained at the length $\displaystyle 120$ cm of wire. Now when the same cell is shunted with $\displaystyle 12 \Omega$ resistance, the balance is shifted to a length of $\displaystyle 180$ cm . The internal resistance of cell is $\displaystyle \_\_\_\_$ $\displaystyle \Omega$
Official answer
From NTA’s final answer key for this paper.
(4)
$\displaystyle 4$
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JEE Main 2026 Physics question, with the answer from NTA’s final answer key. Where our answers come from.